a,70 – 5.(x – 3) = 45

5.(x -3) = 70 - 45

5.(x – 3) = 25

x – 3 = 25 : 5

x – 3 = 5

x = 5 + 3

x = 8

Vậy x = 8

b,\(2x-138=8x9=72\)

\(2x=138+72=210\)

\(x=210:2=105\)

c,\(10+2x=4^2\)\(=16\)

\(2x=16-10=6\)

\(x=6:2=3\)

d, 231 – (x- 6) = 1339 : 13

231 – (x – 6) = 103

x – 6 = 231 – 103

x – 6 = 128

x = 128 + 6

x = 134

Vậy x = 134

a)=>5.(x-3)=70-45               b)=>2x-138=8.9                      c)=>10+2x=4^2          d)=>231-(x-6)=103

=>5.(x-3)=25                            =>2x=138+72                         =>2x=16-10              => x-6=231-103

=>x-3=25:5                               =>x=210:2                                =>2x=6                    =>x-6=128

=>x-3=5                                    =>x=105                                   =>x=3                       =>x=128+6

=>x=8                                                                                                                           =>x=134

cảm ơn bạn nhá

NÓI NHANH

a)x=8 b)x=105   c)x=3      d)x=134

123-5.(x+4)=38

 5(x+4)=123-38

 5(x+4)=85

 x+4=85:5

 x+4=17

 x=17-4

 x=13

10+2x=2.(3²-1)

 10+2x=2.(9-1)

 10+2x=2.8

 2x=16-10

2x=6

 x=6:2

 x=3

2.x-138=2³.3²

 2.x-138=72

 2.x=72+138

 2.x=210

 x=210:2

 x=105

[102+(28-2x)]:20-5=1

 (102+28-2x):20=6

 130-2x=120

 2x=130-120

 2x=10

 x=10:2

 x=5

231-(x-6)=1339:13

 231-(x-6)=103

 x-6=231-103

 x-6=128

 x=128+6

 x=134

123-5.(x+4)=38

5.(x+4)=123-38

5.(x+4)=85

(x+4)=85/5

x+4=17

x=17-4

x=13

10 + 2x = 2(3² - 1)

=> 10 + 2x = 2(9 - 1)

=> 10 + 2x = 2.8

=> 10 + 2x = 16

=> 2x = 16 - 10

=> 2x = 6

=> x = 6/2

=> x = 3

a)13-2(x+1)=7

  2.(x+1)=13-7

  2.(x+1)=6

  x+1=6/2

  x+1=3 

  x=3-1

  x=2

a, 13 - 2 ( x + 1 ) = 7

          2 .( x + 1 ) = 13 - 7
          2 .( x + 1 ) = 6
                x + 1   = 6 : 2
                x + 1    = 3
                x          = 3 - 1
                x           = 4

b)6x+2.4=5².2

6x+2=50

6x=48

x=8

c)420+65.4=(x+175):5+30

(x+175):5+30=680

(x+175):5=650

x+175=3250

x=3075

Tách ?

`a, 70 -5.(x-3) =45`

`=> 5.(x-3)= 70-45`

`=> 5.(x-3)=25`

`=>x-3=25:5`

`=>x-3=5`

`=>x= 5+3`

`=>x=8`

______

`b,10 + 2.x = 4^5:4^3`

`=> 10 + 2.x = 4^(5-3)`

`=> 10 + 2.x =4^2=16`

`=> 2.x=16-10`

`=>2.x=6`

`=>x=6:2`

`=>x=3`

_____

`c,60-3.x-2=51`

`=>  60-3.x= 51+2`

`=> 60-3.x=53`

`=>3.x=60-53`

`=> 3.x= 7`

`=>x= 7/3`

____

`d, 4.x-20=2^5:2^3`

`=> 4.x-20=2^(5-3)`

`=> 4.x-20=2^2`

`=> 4.x= 4+20`

`=>4.x=24`

`=>x=24:4`

`=>x=6`

____

`2^x . 4=16`

`=> 2^x=16:4`

`=>2^x= 4`

`=>2^x=2^2`

`=>x=2`

____

`f, 3^x . 3=243`

`=>3^x=243:3`

`=> 3^x=81`

`=> 3^x=3^3`

`=>x=3`

_____

`g, 64. 4^x =16^8`

`=> 4^3 . 4^x=(4^2)^8`

`=> 4^3 . 4^x = 4^(16)`

`=> 4^x= 4^(16-3)`

`=>4^x=4^(13)`

`=>x=13`

_____

`2^x . 16^2 =1024`

`=> 2^x= 1024 : 16^2`

`=>2^x=4`

`=>2^x=2^2`

`=>x=2`

a: =>5(x-3)=25

=>x-3=5

=>x=8

b: =>2x=16-10=6

=>x=3

c: =>58-3x=51

=>3x=7

=>x=7/3

d: =>4x-20=4

=>4x=24

=>x=6

e: =>2^x=4

=>2^x=2^2

=>x=2

f: =>3^x=81

=>3^x=3^4

=>x=4

g: =>4^x*4^3=4^16

=>x+3=16

=>x=13

h: =>2^x=1024/256=4=2^2

=>x=2

\(a,3\cdot x-15=x+35\)

\(\Rightarrow3x-x=35+15\)

\(\Rightarrow 2x=50\)

\(\Rightarrow x = 50:2\)

\(\Rightarrow x= 25\)

\(b,(8x-16)(x-5)=0\)

\(+, TH1: 8x-16=0\)

\(\Rightarrow8x=16\)

\(\Rightarrow x = 16:8\)

\(\Rightarrow x=2\)

\(+,TH2: x-5=0\)

\(\Rightarrow x =5\)

\(c,x(x+1)=2+4+6+8+10+...+2500\)  \(^{\left(1\right)}\)

Đặt \(A=2+4+6+8+10+...+2500\)

Số các số hạng của \(A\) là: \(\left(2500-2\right):2+1=1250\left(số\right)\)

Tổng \(A\) bằng: \(\left(2500+2\right)\cdot1250:2=1563750\)

Thay \(A=1563750\) vào \(^{\left(1\right)}\), ta được:

\(x\left(x+1\right)=1563750\)

\(\Rightarrow x\left(x+1\right)=1250\cdot1251\)

\(\Rightarrow x =1250\)

#\(Toru\)

e: Ta có: \(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)

\(\Leftrightarrow x^3+8-x^3-2x=15\)

\(\Leftrightarrow2x=-7\)

hay \(x=-\dfrac{7}{2}\)

f: Ta có: \(x^3-6x^2+12x-19=0\)

\(\Leftrightarrow x^3-6x^2+12x-8-11=0\)

\(\Leftrightarrow\left(x-2\right)^3=11\)

hay \(x=\sqrt[3]{11}+2\)

bn ơi chỗ 4 mũ 5 là nhân à